Tuesday, July 1, 2008

Math ~summations of n'th power of positive integers~

For some totally random reason, I have decided to find the formulaes for all the summations of n th power of positive integers when n ranges from 1 -10.

After i finish my homework

On a side note, it was noted that PROESTROGEN SUPPOSED TO HELP PEOPLE PHOTOSYNTHESISE
*ahem* Apparantly during bio class today, when we were supposed to tell the teacher what proestrogen is, some people think its used to help people photosynthesise... or maybe they were just dreaming *ahem*

The formulas will be posted soon....

And here they are!!(currently only up to the 6th power)
Yay finished 7th power(Someone help me factorise)
Done the 8th (Finally.... Someone help me factorise, its a 7 term polynomial!!)

1+2+3+4......+n =

..n(n+1)
------------
......2
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1^2 + 2^2 + 3^2 .......+n^2 =

.n(n+1)(2n+1)
-------------------
...........6

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1^3 + 2^3 + 3^3........+ n^3 =

.(n)(n)(n+1)(n+1)
-----------------------
..............4
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1^4 + 2^4 + 3^4........+ n^4 =

.(n)(n+1)(2n+1)(3n^2 + 3n - 1)
---------------------------------------
........................30
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1^5 + 2^5 + 3^5........+ n^5 =

.(n)(n)(n+1)(n+1)(2n^2 + 2n - 1)
------------------------------------------
..........................12

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1^6 + 2^6 + 3^6........+ n^6 =

.(n)(n+1)(2n+1)(3n^4 + 6n^3 - 3n +1)
-------------------------------------------------
..............................42

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1^7 + 2^7 + 3^7.........+ n^7 =

..(n)(n)(n+1)(n+1)(3n^4 + 6n^3 - n^2 - 4n + 2)
-------------------------------------------------------------
.....................................24

________________________________________________________________

1^8 + 2^8 + 3^8.........+ n^8 =

.(n)(n+1)(2n+1)(5n^6 + 15n^5 + 5n^4 -15n^3 - n^2 + 9n - 3)
------------------------------------------------------------------------------
..................................................90
Sorry for the terrible looks.... hope ill be able to finish until the tenth power by friday

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